Божья Коровка( задание № 1)

Бк 1

A(14;5),  B(3.4;3.7), C(5.3;-2)
AB)Sx=X-Xo=3.4-5=-1.6
Sy=Y-Yo=3.4-14=10.6
|S|=Sx2+Sy2=2.56+112.36=11BC)Sx=5.3-3.4=1.9
Sy=-2-3.7=5.7
|S|=Sx2+Sy2=3.61+32.49=6
AC)Sx=14-5.3=8.7
Sy=5-(-2)=7
|S|=Sx2+Sy2=75.69+49=11

A(9;8), B(9;0), C(-6;0)
AB)Sx=9-9=0



                                                                                      Бк 2

 

Sy=0-8=-8
|S|=Sx2+Sy2=0+64=8
BC)Sx=-6-9=-15
Sy=0-0=0
|S|=Sx2+Sy2=255+0=15
AC)Sx=-6-9=-15
Sy=0-8=-8
|S|=Sx2+Sy2=255+64=17

Бк 3

A(4;9), B(4;-4), C(-6;6)
AB)Sx=4-4=0       Sy=-4-9=-13               |S|=Sx2+Sy2=0+169=13
BC)Sx=-6-4=-10    Sy=6-(-4)=10            |S|=Sx2+Sy2=100+100=14
AC)Sx=-6-4=-10     Sy=6-9=-3                 |S|=Sx2+Sy2=100+9=10